Q19 of 47 Page 1

From the top of a 60m high building, the angles of depression of the top and the bottom of a tower are 45° and 60° respectively. Find the height of the tower. [Take √3 = 1.73]


tan 60° =


CD =


CD = 34.64 m


tan 45° =


AB = 34.64 m [ BE = CD]


Height of tower = ED = BC = 60 – AB = 60 – 34.64 = 25.36 m


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