Q27 of 47 Page 1

Solve for x:

Given,

⇒


⇒ 3 (x2 – 9x + 18 + x2 – 9x + 20) = 10 (x2 – 10x + 24)


⇒ 3 (2x2 – 18x + 38) = 10x2 – 100x + 240


⇒ 6x2 – 54x + 114 = 10x2 – 100x + 240


⇒ 4x2 – 46x + 126 = 0


⇒ 2x2 – 23x + 63 = 0


[By splitting the middle terms]


⇒ 2x2 – 14x – 9x + 63 = 0


⇒ 2x (x – 7) – 9 (x – 7) = 0


⇒ (x – 7) (2x – 9) = 0


⇒ x – 7 = 0 or 2x – 9 = 0


⸫ x = 7 or x =


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