The sum of the 2nd and 7th terms of an A.P. is 30. If its 15th term is 1 less than twice its 8th term. Find the A.P.
The nth term of an A.P. with first term as and common difference as d is given by,
an = a + (n – 1) d
⇒ a2 = a + d
⇒ a7 = a + 6d
According to question,
⇒ a2 + a7 = 30
⇒ a + d + a + 6d = 30
⸫ 2a + 7d = 30 …. (i)
⇒ a15 = a + 14d
⇒ a8 = a + 7d
According to question,
⇒ a15 = 2a8 – 1
⇒ a + 14d = 2 (a + 7d) – 1
⇒ a + 14d = 2a + 14d – 1
⸫ a = 1
Substituting the value of a in eq (i), we get
⸫ d = 4
⸫ The terms of the A.P. are 1, 5, 9, 13, 17, 21, …., nth
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