If A (4, 2), B (7, 6) and C (1, 4) are the vertices of a ΔABC and AD is its median. Prove that the median AD divides ΔABC into two triangles of equal areas.

⸪ AD is the median, D is the mid-point of B and C.
Co-ordinates of D =
= ![]()
Area of triangle
(x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2))
⸫ Area of ΔABD = ![]()
=
= 4.5 sq. units
⸫ Area of ΔADC = ![]()
=
= 4.5 sq. units
⸫ ar (ΔABD) = ar (ΔADC) = 3 sq. units
⸫ The median divides the triangle into two equal areas.
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