Q15 of 47 Page 1

If the point P (k – 1, 2) is equidistant from the points A (3, k) and B (k, 5), find the values of k.

⸪ P is equidistant from A and B, AP = BP

Hence, P is the midpoint of A and B.


Mid-point formula is given by,


(x, y) =


P (k – 1, 2) =


⇒ k – 1 =


⇒ 2k – 2 = 3 + k


⸫ k = 5


⇒ 2 =


⇒ 4 = k + 5


⸫ k = – 1


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