A container open at the tip, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm respectively. Find the cost of milk which can completely fill the container at the rate of ₹21 per litre. [Use π = 22/7![]()
Volume of a frustum of a cone =
πh (R2 + r2 + Rr)
where,
R = upper circular radius
r = lower circular radius
Volume of the cone = ![]()
= ![]()
= ![]()
= 15689.14 cm3
[Using the relation 1 cm3 = 0.001 l]
Volume (in litres) = 15.689 l
⸫ Cost of milk to fill the container = ₹21 × 15.689 l
= ₹329.47
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