Q5 of 49 Page 1

Solve the following quadratic equation for x:

4√3x2 + 5x - 2√3 = 0

4√3x2+5x-2√3 = 0

⇒ 4√3x2+8x-3x-2√3 = 0


⇒ 4x(√3x+2)-√3(√3x+2) = 0


⇒ (4x-√3)(√3x+2) = 0


⇒ (4x-√3) =0 or (√3x+2) = 0


∴ x = (√3/4) or x = (-2/√3)


Thus, the roots of the given Quadratic Equations are (√3/4) and (-2/√3).


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