A die is tossed once. Find the probability of getting an even number or a multiple of 3.

When a die is tossed once-

Sample Space(S) = {1, 2, 3, 4, 5, 6}

No. of Sample Space n(S) = 6

Let M and N be the event of getting an even number and a multiple of 3 respectively.

∴ M = {2,4,6} and n(M) = 3

N = {3,6} and n(N) = 2

M∩N = {6} and n(M∩N) = 1

Let E be the event of getting an even number or a multiple of 3.

∴ P(E) = P(M∪N) = P(M)+P(N)-P(M∩N)

= [n(M)+ n(N)- n(M∩N)]/n(S)

= (3+2-1)/6

= (4/6)

= 2/3

Thus, the probability of getting an even number or a multiple of 3 = 2/3