Q18 of 49 Page 1

A vessel is in the form of a hemispherical bowl surmounted by a hollow cylinder of same diameter. The diameter of the hemispherical bowl is 14 cm and the total height of the vessel is 13 cm. Find the total (inner) surface area of the vessel. [use π = 22/7]

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Given-

Diameter of Hemispherical bowl = 14 cm


∴ Radius of Hemispherical Bowl(r) = Radius of Cylinder(r)


= 7 cm


Total Height of Vessel = 13 cm


∴ Height of Cylinder(h) = 13-7 = 6 cm


Curved Surface Area of Cylinder = 2× π × r× h


= 2× (22/7) × 7× 6


= 264 sq. cm


Curved Surface Area of Hemispherical Bowl = 2 × π × (r)2


= 2× (22/7) × (7)2


= 308 sq. cm


Thus, total (inner) surface area of the vessel = 264+308


= 572 sq. cm


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