Q27 of 49 Page 1

A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person from the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is (i) extremely patient (ii) extremely kind or honest.

Which of the above values you prefer more?

Given-

Total No. of Person = 12


Number of Extremely patient Person = 3


Number of Extremely honest Person = 6


∴ Number of Extremely kind Person = 12 – 3 – 6 = 3


(i) P (extremely patient)


= Number of Extremely patient Person/ Total No. of Person


= 3/12


= 1/4


(ii) P (extremely kind or honest)


= (Number of Extremely kind Person+


Number of Extremely honest Person)/ Total No. of Person


= (6+3)/12


= 9/12


= 3/4


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