Q13 of 49 Page 1

Construct a triangle with sides 5 cm, 4 cm and 6 cm. Then construct another triangle whose sides are times the corresponding sides of first triangle.

Steps of Construction:

1. Draw a line Segment AB = 4 cm. Taking point A as a centre, draw an arc of 5 cm radius. Similarly, taking point B as its center, draw an arc of 6 cm radius. These arcs will intersect each other at point C.


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2. Draw any ray AX making an acute angle with BC on the side opposite to the vertex A.


Locate 3 points [the greater of 2 and 3 in (2/3)] A1, A2, A3, A4 on AX so that


AA1 = A1A2 = A2A3



3. Join BA3 and draw a line through A2 parallel to BA3, intersecting the line segment AB at C′.


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5. Draw a line through B parallel to BC intersecting the line segment AC at C.


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Δ AB'C' is the required Triangle.


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