In Fig. 5, l and m are two parallel tangents to a circle with centre O, touching the circle at A and B respectively. Another tangent at C intersects the line l at D and m at E. Prove that ∠DOE = 90°.

fig.5

Proof:
Let l be XY and m Be X’Y’.
From fig-
∠XDE + ∠X'ED = 180°
[∵ Sum of consecutive interior angles is 180°.]
(1/2) ∠XDE + (1/2) ∠X'ED = 90°
⇒ ∠1 + ∠2 = 90° ...(1)
[∵ OD is equally inclined at the tangents]
In Δ ODE,
(∠1 + ∠2) + ∠3 = 180°
[∵ Angle-sum-property of a Δ]
⇒ 90° + ∠3 = 180° [from (1)]
⇒ ∠3 = 90°
∴ ∠ DOE = 90° …proved
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