In the figure, find the value of y
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Since line EF and AB intersect at O, hence vertically opposite angles ∠EOB and ∠AOF will be equal.
⇒ ∠EOB = ∠AOF = 5y …. (i)
Now two rays EO and BO stands on line CD
⇒ ∠COE + ∠EOB + ∠BOD = 180°
⇒ 4y + 5y + 3y = 180°
... 12y = 180°
⇒ y = 15°.
⇒ ∠EOB = ∠AOF = 5y …. (i)
Now two rays EO and BO stands on line CD
⇒ ∠COE + ∠EOB + ∠BOD = 180°
⇒ 4y + 5y + 3y = 180°
... 12y = 180°
⇒ y = 15°.
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