What value of x would make AOB a line in the figure, if ∠ AOC=4x and ∠ BOC=6x+30° ?
∠ AOC = 4x (given)∠ BOC = 6x+30° (Given)∠ AOC + ∠ BOC = 4x + (6x+30° ) = 180° (Linear pair axiom)⇒ 10x + 30° = 180° ⇒ 10x = 180° - 30° = 150° \\ x = 15°∴ The value of x = 15°.
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