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6. Lines and Angles
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Q49 of 93 Page 6

In the figure, find the value of x. 

Produce AE to meet BC at D.
Now in ΔABD, we have exterior ∠ADC = ∠A + ∠B 
... ∠ADC = 25° + 55° = 80°
Again in ∠DCE, we have
exterior ∠AEC = ∠EDC + ∠ECD
   Þ 󐫬 = ∠ADC + ∠ECD
          x° = 80° + 60° = 140°
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47 The sides AB, BC, CA of a ∠ABC are produced in order, forming exterior angles ∠CBF, ∠ACD and ∠BAE show that ∠ACD + ∠BAE + ∠CBF = 360°
48 In figure, show that AB || EF.
          
50 In the figure l || m, ∠A = 100°, ∠B = 30° find x.
51 In figure, p is a transversal to lines m and n, ∠1 = 60° and Р2 =  of a right angle. Prove that m || n.
           
Questions · 93
6. Lines and Angles
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