If ray OC stands on a line AB such that ∠ AOC = ∠ BOC (Fig), then show that ∠ AOC = 90°.
OC stands on the line AB.
⇒ ∠ AOC + ∠ BOC = 180°
⇒ ∠ AOC = 180° - ∠ BOC
But ∠ AOC = ∠ BOC (Given)
2 ∠ AOC = 180° (Since ∠ AOC = ∠ BOC)
∴ ∠ AOC =
= 90°. ∴ The measure of ∠ AOC = 90°.
⇒ ∠ AOC + ∠ BOC = 180°
⇒ ∠ AOC = 180° - ∠ BOC
But ∠ AOC = ∠ BOC (Given)
2 ∠ AOC = 180° (Since ∠ AOC = ∠ BOC)
∴ ∠ AOC =
= 90°. ∴ The measure of ∠ AOC = 90°. AI is thinking…
Couldn't generate an explanation.
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