If two lines are intersected by a transversal in such a way that the bisectors of a pair of corresponding angles are parallel, then prove that the two lines are parallel.

Given: AB and CD are two lines cut by transversal EF.
QP is the bisector of the angle ∠EQB. SR is the bisector of the corresponding ∠QSD.
PQ || SR.
To prove: AB || CD
Proof: QP || SR and are cut by the transversal EF.
എQP = ∠QSR (Corresponding angles are equal.)------ (1)
PQ is the bisector of ∠EQB
... ∠EQP = ∠PQB = (1/2) ∠EQB ------------------(2)
Similarly, SR is the bisector of ∠QSD
∠QSR = ∠RSD = (1/2) ∠QSD ------------------(3)
But, from (1)
∠EQP = ∠QSR
⇒ (1/2) ∠EQB = (1/2) ∠QSD (From 2 and 3)
... ∠EQB = ∠QSD.
AB and CD are two lines cut by a transversal EF such that corresponding angles.
∠EQB = ∠QSD
... AB || CD (If a transversal intersects two lines such that a pair of corresponding angles are equal then the lines are parallel.)
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