Q50 of 93 Page 6

In the figure l || m, ∠A = 100°, ∠B = 30° find x.

Since l || m and DA is the transversal,  
∠A = ∠CDB = 100° ….(i)
Now in ΔBCD, we have
ext ∠x = ∠CBD +∠CDB
      x = 30° + 100° = 130°
  ... x = 130°

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