In the figure, if l || m, find the value of x.
Since l || m and DC is the transversal
... ∠D + ∠1 = 180° ............................(i)
⇒ 60° + ∠1 = 180° ⇒ ∠1 = 120° ..............(ii)
Now ∠2 = ∠1 = 120° (Vertically opposite angles)...................... (iii)
In Δ ABC, we have ∠A + ∠B + ∠C = 180°
⇒ 25° + x° + 120° = 180°
⇒ x = 180° - 120° - 25° = 35°
... ∠D + ∠1 = 180° ............................(i)
⇒ 60° + ∠1 = 180° ⇒ ∠1 = 120° ..............(ii)
Now ∠2 = ∠1 = 120° (Vertically opposite angles)...................... (iii)
In Δ ABC, we have ∠A + ∠B + ∠C = 180°
⇒ 25° + x° + 120° = 180°
⇒ x = 180° - 120° - 25° = 35°
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