Q1 of 143 Page 6

If θ is an acute angle such that cos θ = 3/5, then =

Given,

cos θ = 3/5

In ∆ ABC,

AC² = AB² + BC²

(5)² = AB² + (3)²

25 = AB² + 9

25 – 9 = AB²

16 = AB²

4 = AB

Therefore,

AB = 4

As,

sin θ = AB/AC = 4/5

tan θ = AB/BC = 4/3

Now,

If A + B = 90° and tan A = 3/4, what is cot B?

If tan A = 5/12, find the value of (sin A + cos A) sec A.

If tan θ = a/b then is equal to

If 5 tan θ – 4 = 0, then the value of is