Q4 of 143 Page 6

If 16 cot x = 12, then equals

Given,


16 cot x = 12


So,


cot x = 12/16


cot x = 3/4


In ∆ ABC,


AC2 = AB2 + BC2


AC2 = (3)2 + (4)2


AC2 = 9 + 16 = 25


AC = 5


Therefore,


sin x = AB/AC = 4/5


cos x = BC/AC = 3/5


Now,



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