Q9 of 143 Page 6

If 3cos θ = 5 sin θ, then the value of is

Given,

3 cos θ = 5 sin θ

In ∆ABC,

AC² = AB² + BC²

AC² = (3)² + (5)²

AC² = 9 + 25 = 34

AC = √34

Therefore,

sin θ = 3/√34

cos θ = 5/√34

sec θ = √34/5

Now,

If tan θ = 3/4, then cos² θ – sin² θ =

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