Q3 of 143 Page 6

If 5 tan θ – 4 = 0, then the value of is

Given,


5 tan θ – 4 = 0


So,


5 tan θ = 4


tan θ = 4/5


In ∆ ABC,


AC2 = AB2 + BC2


AC2 = (4)2 + (5)2


AC2 = 16 + 25


AC2 = 41


AC = √41


Therefore,


sin θ = AB/AC = 4/√41


cos θ = BC/AC = 5/√41


Now,


More from this chapter

All 143 →
1

If θ is an acute angle such that cos θ = 3/5, then =

 2

If tan θ = a/b then is equal to

 4

If 16 cot x = 12, then equals

 5

If 8 tan x = 15, then sin x - cos x is equal to