Q35 of 143 Page 6

In Fig. 5.48, AD = 4 cm BD = 3 cm and CB = 12 cm, find cot θ.

Given,


AD = 4cm


BD = 3 cm


CB = 12 cm


In ∆ABC,


untitled35.bmp


AB2 = AD2 + BD2


AB2 = 42 + 32


AB = √16 + 9 = 5 cm


Then,


cot θ = CB/AB = 12/5

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