Q25 of 143 Page 6

If A + B = 90°, then is equal to

Given,


A + B = 90°


B = 90° - A


Putting this Value in the given equation we get,




∵ tan (90 – A) = Cot A sin(90 – A) = cos A


cot (90 – A) = tan A


sec (90 – A) = cosec A



[∵ cot A = 1/tan A and cosec A = 1/sin A]



⇒ 1 + tan2 A – 1


∵ A + B = 90°


A = 90 – B


So,


⇒ tan2(90 – B)


⇒ cot2B

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