Given,tan θ = 1/√7In ∆ ABC,AC2 = AB2 + BC2AC2 = (1)2 + (√7)2AC2 = 8AC = 2√2Therefore,Now,

Q6 of 143 Page 6

If, then =

Given,

tan θ = 1/√7

In ∆ ABC,

AC² = AB² + BC²

AC² = (1)² + (√7)²

AC² = 8

AC = 2√2

Therefore,

Now,

If 16 cot x = 12, then equals

If 8 tan x = 15, then sin x - cos x is equal to

If tan θ = 3/4, then cos² θ – sin² θ =

If θ is an acute angle such that tan² θ = 8/7, then the value of is