Q3 of 49 Page 5

In adjoining figure 1.14 seg PS ⊥ seg RQ , seg QT ⊥ seg PR. If RQ = 6, PS = 6 and PR = 12, then find QT.

Considering, A(ΔPQR) with base QR

⇒ PS will be the Height


Now, consider the A(ΔPQR) with base PR


⇒ QT will be the Height


∵ , the triangle is same⇒ the area will be same irrespective of the base taken.


And we know that area of triangle = × Base× Height


⇒ ×QR×PS = ×PR×QT


⇒ ×6×6 = ×12×QT


⇒ QT = 3


More from this chapter

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1

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

 2

If figure 1.13 BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find

4

In adjoining figure, AP ⊥ BC, AD || BC, then find A(ΔABC) : A (ΔBCD)

 5

In adjoining figure PQ ⊥ BC, AD ⊥ BC then find following ratios.


(i)

(ii)


(iii)

(iv)