Q9 of 49 Page 21

In the figure, in ΔABC, point D on side BC is such that, ∠BAC = ∠ADC.

Prove that, CA2 = CB × CD


In Δ BAC & Δ ADC

⇒ ∠ BAC ≅ ∠ ADC ……(Given)


And, ∠ACB ≅ ∠DCA ……(common)


⇒ Δ BAC ~ Δ ADC (By AA Test)


⇒ (corresponding sides are proportional)


⇒ CA2 = CB×CD


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