Q4 of 49 Page 21

In ΔABC, AP ⊥ BC, BQ ⊥ AC B- P-C, A-Q - C then prove that, ΔCPA ~ ΔCQB. If AP = 7, BQ = 8, BC = 12 then find AC.

From fig.

⇒ ∠ APC≅ ∠ BQC (∵ AP⊥ BC and BQ⊥ AC)


⇒ Also, ∠ ACP≅ ∠ BCQ (Common)


⇒ Δ CPA~Δ CQB (By AA Test)


⇒


⇒ AC =


⇒AC =


⇒AC = 10.5


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