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Q5 of 49 Page 26

In figure 1.74, PM = 10 cm A(Δ PQS) = 100 sq.cm A (ΔQRS) = 110 sq.cm then find NR.

We know that, Area of triangle = × base× height

⇒


⇒


⇒


⇒ NR = 11 cm


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3

Ratio of areas of two triangles with equal heights is 2 : 3. If base of the smaller triangle is 6 cm then what is the corresponding base of the bigger triangle?

4

In figure 1.73, ∠ABC = ∠DCB = 90° AB = 6, DC = 8 then

6

ΔMNT ~ ΔQRS. Length of altitude drawn from point T is 5 and length of altitude drawn from point S is 9. Find the ratio

7

In figure 1.75, A – D – C and B – E – C seg DE || side AB If AD = 5, DC = 3, BC = 6.4 then find BE.

Questions · 49
1. Similarity
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