Q6 of 49 Page 21

In trapezium ABCD, (Figure 1.60) side AB || side DC, diagonals AC and BD intersect in point O. If AB = 20, DC = 6, OB = 15 then find OD.

In Δ AOB and ΔCOD

⇒ ∠ AOB≅ ∠ COD (opposite angles)


⇒ ∠ CDO≅ ∠ ABO (Alternate angles ∵ AB||DC)


⇒ Δ AOB ~ Δ COD (By AA Test)


⇒ (corresponding sides are proportional)


⇒ OD =


⇒ OD =


⇒ OD = 4.5


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