In the figure 1.44, X is any point in the interior of triangle. Point X is joined to vertices of triangle. Seg PQ || seg DE, seg QR || seg EF. Fill in the blanks to prove that, seg PR || seg DF.

Proof : IN ![]()

(Basic proportionality theorem)
In ![]()

(converse of basic proportionality theorem)
Proof: In ΔXDE, PQ||DE….. (Given)
∴
…..(I)
(Basic proportionality theorem)
In ΔXDE, QR||EF …….(Given)
∴
………(II) (Basic Proportionality Theorem)
∴
……… from (I) and (II)
∴ seg PR||Seg DE ………..
(converse of basic proportionality theorem)
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