Q1 of 49 Page 25

The ratio of corresponding sides of similar triangles is 3 : 5; then find the ratio of their areas.

Theorem: When two triangles are similar, the ratio of areas of those triangles is equal to the ratio of the squares of their corresponding sides.

⇒ Ratio of areas = 32:52


⇒ Ratio of areas = 9 : 25


More from this chapter

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8

In the figure, seg AC and seg BD intersect each other in point P and Prove that, ΔABP ~ ΔCDP

 9

In the figure, in ΔABC, point D on side BC is such that, ∠BAC = ∠ADC.

Prove that, CA2 = CB × CD


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If ΔABC ~ ΔPQR and AB: PQ = 2:3, then fill in the blanks.

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If ΔABC ~ ΔPQR, A (ΔABC) = 80, A(ΔPQR) = 125, then fill in the blanks.