Q8 of 49 Page 21

In the figure, seg AC and seg BD intersect each other in point P and Prove that, ΔABP ~ ΔCDP

In Δ APB & Δ CPD


⇒ ……(Given)

And, ∠ CED ≅ ∠ BET (vertically opposite angles)


⇒ Δ APB ~ Δ CPD (By SAS Test)

More from this chapter

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6

In trapezium ABCD, (Figure 1.60) side AB || side DC, diagonals AC and BD intersect in point O. If AB = 20, DC = 6, OB = 15 then find OD.

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□ ABCD is a parallelogram point E is on side BC. Line DE intersects ray AB in point T. Prove that DE × BE = CE × TE.

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In the figure, in ΔABC, point D on side BC is such that, ∠BAC = ∠ADC.

Prove that, CA2 = CB × CD


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The ratio of corresponding sides of similar triangles is 3 : 5; then find the ratio of their areas.