Q13 of 113 Page 110

The digit in the tens place of a two-digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is

Let the digit at unit’s place be b.

Then the digit at ten’s place = (3 + b)


The Number = 10(3 + b) + b = 30 + 10b + b = 11b + 30

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