Solve the following question.
1 – (x – 2) – [(x-3) – (x-1)] = 0
Given equation is,
⇒ 1-(x-2)-[(x-3)-(x-1)] = 0
⇒ 1-x + 2-[x-3-x + 1] = 0
⇒ 1-x + 2-[-2] = 0
⇒ 3-x + 2 = 0
⇒ 5-x = 0
⇒ -x = -5 (transposing 5 to RHS)
⇒ x = 5
⇒ Hence value of x is 5.
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