Q60 of 113 Page 110

Solve the following question.

4t – 3 – (3t + 1) = 5t – 4


Given equation is,


⇒ 4t-3-(3t + 1) = 5t-4


⇒ 4t-3-3t-1 = 5t-4


⇒ t-4 = 5t-4


⇒ t-5t = -4 + 4 (transposing 5t to LHS and – 4 to RHS)


⇒ -4t = 0



⇒ Hence value of t is 0.


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