Q3 of 40 Page 92

The larger of two supplementary angles exceeds the smaller by 18o. Find the angles.

Let the larger of the two supplementary angles be ‘y’ and the smaller angle be ‘x’

Therefore, x + y = 180 …I


(∵ sum of supplementary angles is 180° )


Also, y = x + 18 (∵ Given) …..II


Substituting II in I, we get,


x + x + 18 = 180


⇒ 2x + 18 = 180


⇒ 2x = 180 – 18


⇒ 2x = 162


⇒ x = 81°


Substitute x = 81 in II


y = 81 + 18 = 99°


Therefore, measure of larger angle is 99° and the measure of the smaller angle is 81°


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