Solve each of the following pairs of equations by reducing them to a pair of linear equation.
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6x + 3y = 6xy
2x + 4y = 5xy
⇒
….I
⇒
….II
Let
= p and
= q
6p + 3q = 6
2p + 4q = 5
Multiplying eq. IV by 3 and subtracting from Eq. III
6p + 3q = 6
6p + 12q = 15
-9q = -9
q = 1
substitute the value of q in III
6p + 3(1) = 6
p = ![]()
But,
⇒ x = 2
⇒ y = -1
Couldn't generate an explanation.
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