Formulate the following problems as a pair of equation and then find their solution.
2 women and 5 men can together finish an embroidery work in 4 days while 3 women and 6 men can finish it in 3 days. Find the time taken by 1 woman alone and 1 man alone to finish the work.
Let the time taken by one woman to finish the work = x days
Work done by one women in one day =
days
Let the time taken by one man to finish the work = y days
Work done by one men in one day =
days
Now, 2 women and 5 men can finish the work in 4 days
So,
⇒
…I
Also, 3 women and 6 men can finish the work in 3 days
So,
⇒
…II
Let
be a and
be b
8a + 20b = 1 …III
9a + 18b = 1 …IV
Multiplying Eq. III by 9 and Eq. IV by 8 and solving
72a + 180b = 9
72a + 144b = 8
_- - - _
36b = 1
b = ![]()
substituting value of b in Eq. III
8a + 20 ×
= 1
288a + 20 = 36
288a = 16
a = ![]()
⇒ x = 18
⇒ y = 36
Number of days by man = 18;
Number of days by woman = 36
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