Solve each of the following pairs of equations by reducing them to a pair of linear equation.


and ![]()
Let
= m and
= n
m + n
⇒ 4(m + n) = 3 ⇒4m + 4n = 3…(I)
⇒ 8(m-n) = -1 × 2 ⇒8m-8n = -2…(II)
Multiply Eq. I by 2
8m + 8n = 6
8m - 8n = -2
16m = 4
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Substituting
in Eq. II
– 8n = -2
⇒ 2 – 8n = -2
⇒ -8n = -4
⇒ n = ![]()
∴
⇒
⇒ 4 = 3x + y ⇒ 4 = 3x + y ![]()
∴
⇒
⇒ 2 = 3x-y ⇒ 2 = 3x-y ….IV
Equating Eq. III and IV
3x + y = 4
3x-y = 2
6x = 6
x = 1
Substituting x = 1![]()
3×1 + y = 4
![]()
![]()
![]()
Hence, x = 1 and y = 1
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