Solve each of the following pairs of equations by reducing them to a pair of linear equation.


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Let
= p and
= q
10p + 2q = 4 …I
15p – 5q = -2 …II
Multiply Eq. I by 5 and Eq. II by 2
50p + 10q = 20
30p – 10q = -4
80p = 16
p = ![]()
substitute value of p in eq. I
10
+ 2q = 4
⇒ 2 + 2q = 4
⇒ 2q = 2
⇒ q = 1
But,
⇒ 5 = x + y …III
⇒ 1 = x – y ⇒ y = x – 1
Substitute value of y in eq. III
x + x – 1 = 5
⇒ 2x = 6
⇒ x = 3
∴ y = 3 – 1 = 2
x = 3 and y = 2
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