Q1 of 40 Page 98

Solve each of the following pairs of equations by reducing them to a pair of linear equation.




Let be p andbe q,


We get the following pair of linear equations:


5p + q = 2 …III


6p – 3q = 1 …IV


Using the elimination method:


Multiplying eq. III by 3 and adding to IV, we get


15p + 3q = 6


6p – 3q = 1


21p = 7


⇒ p =


Substitute the value of p in eq. III



⇒


⇒


But, ⇒ 3 = x – 1 ⇒ x = 4


⇒ 3 = y – 2 ⇒ y = 5


So, x = 4 and y = 5


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