Q1 of 40 Page 98

Solve each of the following pairs of equations by reducing them to a pair of linear equation.


and

Let be p and be q


2p + 3q = 2 …III


4p – 9q = -1 …IV


Multiplying eq. III by 3 and subtracting with eq. IV, we get


6p + 9q = 6


4p – 9q = -1


10p = 5


p =


substitute value of p in Eq. III


+ 3q = 2


⇒ 3q = 2 – 1


⇒ q =


But, ⇒ ⇒ ⇒ x = 4


⇒ ⇒ ⇒ y = 9


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