An algebra textbook has a total of 1382 pages. It is broken up into two parts. The second part of the book has 64 pages more than the first part. How many pages are in each part of the book?
Let the number of pages in the first part be x and in the second part be y.
Total pages number of pages is 1382,
Hence, x + y = 1380 …I
The second part of the book has 64 pages more than the first part
y = x + 64 …II
substituting value of y in equation I
x + x + 64 = 1382
2x = 1382 – 64
2x = 1318
x = 659
substituting the value of x in equation (2),
y = 659 + 64
y = 723
the pages in the first book are 659 and the pages in the second part are 723.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.