Q11 of 84 Page 114

Show that (4, 1) is equidistant from the points (−10, 6) and (9, −13).

Formula used:


Let the points be A (4, 1), B (–10, 6) and C (9, –13)


Distance of AB


⇒ AB = √ ((–10 – 4)2 + (6 – 1)2)


⇒ AB = √ ((–14)2 + (5)2)


⇒ AB = √ (196 + 25


⇒ AB = √ 221


Distance of BC


⇒ BC = √ ((9 – 4)2 + (–13 – 1)2)


⇒ BC = √ ((5)2 + (–14)2)


⇒ BC = √ (25 + 196


⇒ BC = √ 221


∴ AB = BC = √ 221


More from this chapter

All 84 →
9

Examine whether the following points taken in order form a rectangle.

(−3, 0), (1, −2), (5, 6) and (1, 8)

 10

If the distance between two points (x,7) and (1, 15) is 10, find x.

 12

If two points (2, 3) and (−6, −5) are equidistant from the point (x, y), show that x + y + 3 = 0.

 13

If the length of the line segment with end points (2, −6) and (2, y) is 4, find y.