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5. Coordinate geometry
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Q16 of 84 Page 114

Find the radius of the circle whose center is (3, 2) and passes through (−5, 6).

Formula used:


Let the point be A (–5, 6) and O (3, 2)


Distance of OA


⇒ OA = √ ((–5 – 3)2 + (6 – 2)2)


⇒ OA = √ ((–8)2 + (4)2)


⇒ OA = √ (64 + 16)


⇒ OA = √ 80


⇒ OA = 4√5


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14

Find the perimeter of the triangle with vertices (i) (0, 8), (6, 0) and origin; (ii) (9, 3), (1, −3) and origin.

15

Find the point on the y–axis equidistant from (−5, 2) and (9, −2) (Hint: A point on the y–axis will have its x–coordinate as zero).

17

Prove that the points (0, −5), (4, 3) and (−4, −3) lie on the circle centered at the origin with radius 5.

18

In the Fig. 5.20, PB is perpendicular segment from the point A (4, 3). If PA = PB then find the coordinates of B.

Questions · 84
5. Coordinate geometry
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