If origin is the center of a circle with radius 17 units, find the coordinates of any four points on the circle which are not on the axes. (Use the Pythagorean triplets)
Formula used: ![]()
Let the point be A (x, y)
Center is at origin (0, 0)
Distance of OA
⇒ OA = √((x – 0)2 + (y – 0)2)
⇒ OA = √ ((x)2 + (y)2)
⇒ OA = √ x2 + y2
Squaring both sides
⇒ (0A)2 = x2 + y2
⇒ (17)2 = x2 + y2
Using Pythagorean triplet
x and y can 8 and 5 or vice–a–versa.
∴ x = ± 8 or ±15
y = ± 8 or ±15
Hence, coordinate on circle other than coordinates on axis are
(8, 15), (–8, –15), (–8, 15) and (8, –15)
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