Q12 of 131 Page 226

In Fig. 9.19, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4cmrespectively. If EF = 10 cm, then area of EFGH is

In parallelogram EFGH,


EF = HG = 10 cm [Given]


Area of parallelogram EFGH = Base × Corresponding height = 10 × 4 = 40 cm2

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