Area of a triangle PQR right-angled at Q is 60 cm2 (Fig. 9.43). If the smallest side is 8cm long, find the length of the other two sides.


Given, area of ∆PQR = 60 cm2 with PQ = 8 cm
We know that, Area of triangle =
× b × h
Area of ∆PQR = 60 cm2
× PQ × QR = 60
× 8 × QR = 60
∴ QR = 15 cm
Applying Pythagoras theorem in ∆PQR,
(PQ)2 + (QR)2 = (PR)2
(8)2 + (15)2 = (PR)2
(PR)2 = 64 + 225 = 289
AC =√289 = 17 cm
Hence, the length of two sides are 15 cm and 17 cm.
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